Exercise 2.3.3 (First examples, part 3)

Question

Solve the set of congruences $x\equiv 1 \pmod 4, x \equiv 0 \pmod 3, x \equiv 5 \pmod 7$.

Richard Ganaye · Accepted Answer

ewcommand{\Z}{\mathbb{Z}}

\begin{proof} Here $4,3,7$ are relatively prime by pairs. A solution is $x_0 = 33$. Therefore the solutions are
$$x = 33 + k84,\ k \in \Z.$$
\end{proof}

Exercise 2.3.3 (First examples, part 3)

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Exercise 2.3.3 (First examples, part 3)

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