Exercise 3.1.1 (Integral part of $x$)

Find 3 2 , 3 2 , π , 7 , and x for 0 x < 1 .

Answers

Proof. By definition, for all real numbers x , n ,

n = x { n , n x < n + 1 .

  • 1 3 2 < 2 , thus 3 2 = 1 .
  • 2 3 2 < 1 , thus 3 2 = 2 .
  • 3 π < 4 , thus π = 3 .
  • 7 7 < 6 , thus 7 = 7 .
  • If 0 x < 1 , then x = 0 .
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2024-10-16 08:51
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