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Exercise 3.2.19* (Biquadratic character of $-1$ modulo $p$)
Show that is a divisor of numbers of both of the forms , , if and only if it is a divisor of some number of the form .
Answers
Proof. If , both propositions are true for , , .
The odd prime is a divisor of numbers of both of the forms , if and only if and are quadratic residues modulo , if and only if
This is equivalent to
that is,
Since , these conditions are equivalent to
This first part shows that for every odd prime ,
Moreover, by Theorem 2.37, we may characterize the fourth powers modulo :
(biquadratic character of ).
We have proved
that is, is a divisor of numbers of both of the forms , , if and only if it is a divisor of some number of the form . □