Homepage Solution manuals Ivan Niven An Introduction to the Theory of Numbers Exercise 5.4.13 (Equation $x^n + y^n = z^n$ if $n \equiv 0 \pmod 4$)

Exercise 5.4.13 (Equation $x^n + y^n = z^n$ if $n \equiv 0 \pmod 4$)

Show that Fermat’s equation (5.28) has no solution in positive integers x , y , z , if n is a positive integer, n 0 ( mod 4 ) .

Answers

Proof. We write n = 4 m , where m is a positive integer. If Fermat’s equation x n + y n = z n had a solution in positive integers x , y , z , then

( x m ) 4 + ( y m ) 4 = ( z m ) 4 .

This shows that the equation X 4 + Y 4 = Z 4 has a solution ( X , Y , Z ) = ( x m , y m , z m ) in positive integers. This is impossible by Theorem 5.10.

The Fermat’s equation x n + y n = z n has no solution in positive integers x , y , z , if n is a positive integer, n 0 ( mod 4 ) . □

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2025-04-23 08:44
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