Exercise 5.7.3 (Curve passing through given points)

Show that the general polynomial of degree d in two variables has ( d + 2 2 ) coefficients. Deduce that if ( d + 2 2 ) 1 points in the plane are given, then there exists a curve of degree d that passes through them.

Answers

Proof. A general polynomial f K [ x , y ] of degree d in two variables is given by f ( x , y ) = ( i , j ) A a i , j x i y j , where A = { ( i , j ) 2 i + j d } . Here K is any field, and a i , j K .

Write A k = { ( i , j ) 2 i + j = k } . Then A is the disjoint union of the A k for 0 k d , so that

Card ( A ) = k [ [ 0 , d ] ] Card ( A k ) .

Since A k = { ( 0 , k ) , ( 1 , k 1 ) , , ( k , 0 ) } , we obtain Card ( A k ) = k + 1 , thus

Card ( A ) = k [ [ 0 , d ] ] ( k + 1 ) = ( d + 1 ) ( d + 2 ) 2 = ( d + 2 2 ) .

Consider ( d + 2 2 ) 1 points M 1 , M 2 , , M ( d + 1 ) ( d + 2 ) 2 1 in the plane, where the coordinates of M k are ( x k , y k ) , without any condition concerning these points. Then the curve f ( x , y ) = 0 passes through them if and only if

f ( x k , y k ) = ( i , j ) A a i , j x k i y k j = 0 1 i ( d + 1 ) ( d + 2 ) 2 1 .

The unknowns a ij are solutions of this homogeneous linear system with ( d + 2 2 ) 1 equations and ( d + 2 2 ) unknowns. Therefore there is a nontrivial solution of this system, so there exists a curve f ( x , y ) = 0 of degree at most d that passes through the points M k .

If deg ( f ) < d , we take g = fh , where h is some polynomial with degree d deg ( f ) . Then the curve with equation g ( x , y ) = 0 has degree d and passes through the points M k .

Example: Given nine points, there is some cubic which passes through these nine points. □

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2025-05-17 09:05
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