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Exercise 5.7.3 (Curve passing through given points)
Show that the general polynomial of degree in two variables has coefficients. Deduce that if points in the plane are given, then there exists a curve of degree that passes through them.
Answers
Proof. A general polynomial of degree in two variables is given by , where . Here is any field, and .
Write . Then is the disjoint union of the for , so that
Since , we obtain , thus
Consider points in the plane, where the coordinates of are , without any condition concerning these points. Then the curve passes through them if and only if
The unknowns are solutions of this homogeneous linear system with equations and unknowns. Therefore there is a nontrivial solution of this system, so there exists a curve of degree at most that passes through the points .
If , we take , where is some polynomial with degree . Then the curve with equation has degree and passes through the points .
Example: Given nine points, there is some cubic which passes through these nine points. □