Exercise 32.1

Show that a closed subspace of a normal space is normal.

Answers

Proof. Suppose Y is our closed subspace of our normal space X, and A,B Y disjoint and closed. By Theorem 17.3, A,B are closed in X. Let U,V be a separation of A,B in X. Then, Y U,Y V separate A,B in Y , and so Y is normal. □

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2021-12-21 20:01
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