Exercise 1.1.34

Question

If $g(x)=\dfrac{x}{\sqrt{x+1}},$ find $g(0), g(3), 5g(a), \frac{1}{2}g(4a), g(a^2), [g(a)]^2, g(a+h)$, and $g(x-a)$.

Khagan Gulusoy · Accepted Answer

$$
\begin{aligned}
& g(0)=\frac{0}{\sqrt{0+1}}=0 ; \
& g(3)=\frac{3}{\sqrt{3+1}}=\frac{3}{\sqrt{4}}=\frac{3}{2}; \
& 5 g(a)=5 \cdot \frac{a}{\sqrt{a+1}}=\frac{5 a}{\sqrt{a+1}} ; \
& \frac{1}{2} g(4 a)=\frac{1}{2} \cdot \frac{4 a}{\sqrt{4 a+1}}=\frac{2 a}{\sqrt{4 a+1}} ; \
& g\left(a^2ight)=\frac{a^2}{\sqrt{a^2+1}} ; \
& {[g(a)]^2=\left(\frac{a}{\sqrt{a+1}}ight)^2=\frac{a^2}{a+1} ;} \
& g(a+h)=\frac{a+h}{\sqrt{a+h+1}} ; \
& g(x-a)=\frac{x-a}{\sqrt{x-a+1}}
\end{aligned}
$$

Exercise 1.1.34

Answers

Comments

Exercise 1.1.34

Answers

Comments

Add answer