Exercise 1.3.55 (55-56)

Question

Use the table to evaluate each expression.
    \begin{table}[H]\centering
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline$x$ & 1 & 2 & 3 & 4 & 5 & 6 \
\hline$f(x)$ & 3 & 1 & 5 & 6 & 2 & 4 \
\hline$g(x)$ & 5 & 3 & 4 & 1 & 3 & 2 \
\hline
\end{tabular}
\end{table}
\begin{enumerate}
\item [55.] \begin{enumerate}[label=(\alph*)]
\item $f(g(3))$
\item $g(f(2))$
\item $(f\circ g)(5)$
\item $(g \circ f)(5).$
\end{enumerate}
\item [56.] \begin{enumerate}[label=(\alph*)]
\item $g(g(g(2)))$
\item $f(f(f(1)))$
\item $(f\circ f\circ g)(1)$
\item $(g \circ f\circ g)(3).$
\end{enumerate}
\end{enumerate}

Khagan Gulusoy · Accepted Answer

\begin{enumerate}
\item [55.] \begin{enumerate}[label=(\alph*)]
\item $$f(g(3))=f(4)=6.$$
\item $$g(f(2))=g(1)=5.$$
\item $$(f \circ g)(5)=f(g(5))=f(3)=5.$$
\item $$(g \circ f)(5)=g(f(5))=g(2)=3.$$
\end{enumerate}
\item [56.] \begin{enumerate}[label=(\alph*)]
\item $$g(g(g(2)))=g(g(3))=g(4)=1.$$
\item $$(f \circ f \circ f)(1)=f(f(f(1)))=f(f(3))=f(5)=2.$$
\item $$(f \circ f \circ g)(1)=f(f(g(1)))=f(f(5))=f(2)=1.$$
\item $$(g \circ f \circ g)(3)=g(f(g(3)))=g(f(4))=g(6)=2.$$
\end{enumerate}
\end{enumerate}

Exercise 1.3.55 (55-56)

Answers

Comments


$x$	1	2	3	4	5	6

$f (x)$	3	1	5	6	2	4

$g (x)$	5	3	4	1	3	2

Exercise 1.3.55 (55-56)

Answers

Comments

Add answer