Exercise 2.11

Proposition 2.10. Let M , N , and P be smooth manifolds with or without boundary.

(a)
Every constant map c: M N is smooth.
(b)
The identity map of M is smooth.
(c)
If U M is an open submanifold with or without boundary, then the inclusion map U M is smooth.
(d)
If F : M N and G : N P are smooth, then so is G F : M P .

Exercise 2.11 Prove parts (a)–(c) of the preceding proposition.

Answers

(a)
Let c : M N be a constant map of value c N 1. Fix p M and let ( U , φ ) be a chart containing p . Picking any chart ( V , ψ ) that contains the constant value c N will do the job since U c 1 ( V ) = U = U is open. The coordinate representation ψ c φ 1 = ψ ( c ) : φ ( U ) ψ ( V )

is a constant function of value φ ( c ) . Since a constant function between subsets of Euclidean spaces is smooth in the sense of ordinary calculus, the map c must be smooth.

(b)
Let Id : M M be the identity map. Fix p M and let ( U , φ ) be a chart containing p . Then ( U , φ ) is also a chart that contains Id ( p ) and satisfies U Id ( U ) = U . The coordinate representation φ Id φ 1 = Id n : φ ( U ) φ ( U )

is an identity function. Since an identity function between subsets of Euclidean spaces is smooth in the sense of ordinary calculus, the map Id must be smooth.

(c)
Let ι : U M be the inclusion map of U 2. Fix p U and let ( U ~ , φ ~ ) be a chart of U containing p . Note that ( U , φ ) is also a chart of M that in particular contains ι ( p ) = p and satisfies ι ( U ) = Id | U ( U ) = U . The coordinate representation is φ ι φ 1 = φ Id | U φ 1 = Id n : φ ( U ) φ ( U ) .

By the same argument as in the previous part of the exercise, ι is smooth.

1We use c to denote both the function c : M N and the constant value c N .

2I.e., the restriction of identity to U .

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2023-08-27 13:19
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