Homepage Solution manuals John Lee Introduction to Smooth Manifolds Exercise 2.9 (Smoothness does not depend on the choice of charts II)

Exercise 2.9 (Smoothness does not depend on the choice of charts II)

Suppose that F : M N is a smooth map between smooth manifolds with or without boundary. Show that the coordinate representation of F with respect to every pair of smooth charts for M and N is smooth.

Answers

Proof. Let ( U ~ , φ ~ ) and ( V ~ , ψ ~ ) be smooth charts for M and N respectively and consider the set U ~ F 1 ( V ~ ) . If U ~ F 1 ( V ~ ) is empty, the assertion follows vacuously, so assume that it is non-empty. By the smoothness of F , for each p U ~ F 1 ( V ~ ) , we can find a chart ( U p , φ ) containing p and a chart ( V p , ψ ) containing F ( p ) such that F ( U p ) V p and the coordinate representation

ψ F φ 1 : φ ( U p ) ψ ( V p )
(1)

is smooth. Furthermore, by smooth compatibility of ( U ~ , φ ~ ) and ( U p , φ ) , there is a smooth transition map

φ φ ~ 1 : φ ~ ( U ~ U p ) φ ( U ~ U p ) .
(2)

Similarly, there is a smooth transition map between ( V ~ , ψ ~ ) and ( V , ψ ) :

ψ ~ ψ 1 : ψ ( V ~ V p ) ψ ~ ( V ~ V p ) .
(3)

Composing all three smooth maps into one, we obtain a smooth coordinate representation

( ψ ~ ψ 1 ) ( ψ F φ 1 ) ( φ φ ~ 1 ) = ψ ~ F φ ~ 1 : φ ~ ( U ~ U p F 1 ( V ~ ) ) ψ ~ ( V ~ )

Since our choice of p U ~ F 1 ( V ~ ) was arbitrary, F must be smooth with respect to ( U ~ , φ ~ ) and ( V ~ , ψ ~ ) . □

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2023-08-27 09:52
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