Homepage Solution manuals John Lee Introduction to Smooth Manifolds Exercise 3.19 (Tangent bundle of a smooth manifold with boundary is a smooth manifold with boundary)

Exercise 3.19 (Tangent bundle of a smooth manifold with boundary is a smooth manifold with boundary)

Suppose M is a smooth manifold with boundary. Show that TM has a natural topology and smooth structure making it into a smooth manifold with boundary, such that if ( U , ( x i ) ) is any smooth boundary chart for M , then rearranging the coordinates in the natural chart ( π 1 ( U ) , ( x i , v i ) ) for TM yields a boundary chart ( π 1 ( U ) , ( v i , x i ) ) .

Answers

We use Smooth Manifold Chart Lemma (Exerise 1.43) the same way that Lemma 1.35 was used in Proposition 3.18. We must, however, modify (3.13) and add an additional argument to account for the boundary charts.

Let A = { ( U α , φ α ) } α A be the smooth structure of the manifold with boundary M . For each coordinate map ( U α , φ α ) in A define

φ ~ α : π 1 ( U α ) TM n × φ ( U α ) n × n = 2 n , φ ~ α ( p , i = 1 n v i x i | p ) = ( i = 1 n v i e i , φ α ( p ) ) .
(3.13)

In other words, we have a collection { π 1 ( U α ) } α A of subsets of M together with maps φ ~ α : π 1 ( U α ) 2 n . The rest of the proof follows analogously to the proof of Proposition 3.18.

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2023-09-01 10:11
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