Exercise 3.7 (Properties of differentials)

Proposition 3.6 (Properties of Differentials). Let M , N , and P be smooth manifolds with or without boundary, let F : M N and G : N P be smooth maps, and let p M .

(a)
d F p : T p M T F ( p ) N is linear.
(b)
d ( G F ) p = d G F ( p ) d F p : T p M T G F ( p ) P .
(c)
d ( Id M ) p = Id T p M : T p M T p M .
(d)
If F is a diffeomorphism, then d F p : T p M T F ( p ) N is an isomorphism, and ( d F p ) 1 = d ( F 1 ) F ( p ) .

Exercise 3.7. Prove Proposition 3.6.

Answers

(a)
Let v , w T p M and c be arbitrary. For all f C ( N ) , we have: d F p ( c v + w ) ( f ) = ( c v + w ) ( f F ) = c v ( f F ) + w ( f F ) = c d F p ( v ) ( f ) + d F p ( w ) ( f ) .

Since we have verified the function equality for all inputs f , it follows that

d F p ( cv + w ) = c d F p ( v ) + d F p ( w ) .
(b)
Let v T p M be arbitrary. For all f C ( P ) , we have:
d G d F ( v ) u T G ( F ( p ) ) P ( f ) C ( P ) = d G ( d F ( v ) w T F ( p ) N ) ( f ) C ( P ) = d F ( v ) w T F ( p ) N ( f G ) C ( N ) = v ( f G F ) C ( M ) = d ( G F ) ( v ) u T G ( F ( p ) ) P ( f ) C ( P )

Since we have verified the function equality for all inputs f , it follows that

d ( G F ) p ( v ) = ( d G F ( p ) d F p ) ( v ) .
(c)
For all f C ( P ) , we have: d ( Id ) p ( v ) ( f ) = v ( f Id M ) = v ( f ) = ( Id T p M ( v ) ) ( f ) .

Since we have verified the function equality for all inputs f , it follows that

d ( Id M ) p ( v ) = Id T p M ( v ) .
(d)
Suppose that F is a diffeomorphism. Since Id M = F 1 F , by parts (b) and (c) of this exercise, we have Id T p M = d ( Id M ) p = d ( F 1 F ) p = d ( F 1 ) F ( p ) d F p .

Similarly, since Id N = F F 1 , we have

Id T p N = d ( Id N ) F ( p ) = d ( F F 1 ) p = d F p d ( F 1 ) F ( p ) .

Hence, d F p and d ( F 1 ) F ( p ) are linear isomorphisms and inverses of each other.

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2023-08-29 13:30
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