Exercise 8.9

Proposition 8.8. Let M be a smooth manifold with or without boundary.

(a)
If X and Y are smooth vector fields on M and f , g C ( M ) , then fX + gY is a smooth vector field.
(b)
𝔛 ( M ) is a module over the ring C ( M ) .

Exercise 8.9. Prove Proposition 8.8.

Answers

By Proposition 8.1, the coordinate representations X ^ of X and Y ^ of Y

X ^ ( x ) = ( x 1 , , x n , X 1 ( x ) , , X n ( x ) ) Y ^ ( x ) = ( x 1 , , x n , Y 1 ( x ) , , Y n ( x ) )

are smooth in the sense of ordinary calculus. This implies that the coordinate representation

Z ^ = ( x 1 , , x n , ( f X 1 + g Y 1 ) ( x ) , , ( f X n + g Y n ) ( x ) )

must be smooth in the sense of ordinary calculus. Since our choice of the coordinate chart was arbitrary, the corresponding vector field fX + gY must be smooth.

By Exercise 2.1, C ( M ) is a commutative ring. Using part (a) of this exercise or using the same strategy (verifying that the coordinate representation satisfies the corresponding smoothness criterion), it is then easy to see that 𝔛 ( M ) is a module over C ( M ) (cf. page 617), i.e.:

(i)
𝔛 ( M ) is an abelian group under addition.
(ii)
Scalar multiplication satisfies f ( gX ) = ( fg ) X for all  X 𝔛 ( M )  and  f , g C ( M ) ; 1 X = X for all  X 𝔛 ( M ) .
(iii)
Scalar multiplication and module addition are related by distributive laws: ( f + g ) X = fX + gX for all  X 𝔛 ( M )  and  f , g C ( M ) ; f ( X + Y ) = fX + fY for all  X , Y 𝔛 ( M )  and  f C ( M ) .
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2023-09-02 13:21
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