Homepage › Solution manuals › John Lee › Introduction to Smooth Manifolds › Exercise 8.9
Exercise 8.9
Proposition 8.8. Let be a smooth manifold with or without boundary.
- (a)
- If and are smooth vector fields on and , then is a smooth vector field.
- (b)
- is a module over the ring .
Exercise 8.9. Prove Proposition 8.8.
Answers
By Proposition 8.1, the coordinate representations of and of
are smooth in the sense of ordinary calculus. This implies that the coordinate representation
must be smooth in the sense of ordinary calculus. Since our choice of the coordinate chart was arbitrary, the corresponding vector field
must be smooth.
By Exercise 2.1, is a commutative ring. Using part (a) of this exercise or using the same strategy (verifying that the coordinate representation satisfies the corresponding smoothness criterion), it is then easy to see that is a module over (cf. page 617), i.e.:
- (i)
- is an abelian group under addition.
- (ii)
- Scalar multiplication satisfies
- (iii)
- Scalar multiplication and module addition are related by distributive laws: