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Problem 3-2 (The tangent space to a product manifold)
Proposition 3.14 (The Tangent Space to a Product Manifold). Let be smooth manifolds, and for each , let be the projection onto the factor. For any point , the map
defined by
is an isomorphism. The same is true if one of the spaces is a smooth manifold with boundary.
Answers
Linearity. First, we demonstrate that is a linear map. Obviously, we use the fact that each component in itself is linear (cf. Proposition 3.6(a)). Let and be arbitrary. We then have
Bijectivity. Now we demonstrate that is bijective. To do so, we explicitly provide an inverse map by reverse engineering . For each , let be the embedding onto the factor of , i.e., . For any point , the map
defined by
| (1) |
is the inverse for . To see why, consider some . Unwrapping the definitions and using various properties from Proposition 3.6, we obtain
Notice that the functions themselves satisfy . In other words, is the identity function for and the constant function for . By Proposition 3.6, and by Problem 3.1, for . We get
In other words, is the identity function on . Thus, is surjective. Since is a linear transformation and since and have the same dimension1, must be a bijection.
Manifolds with boundary. Suppose that is a smooth manifold with boundary for some . Then is a smooth manifold with boundary as well. Therefore, it has a tangent space at each point with well-defined differentials. We can therefore apply the same proof to the case of a manifold with boundary.
1cf. Example 1.34 and Proposition 3.10/3.12 and the fact that a tangent space is a manifold. Both spaces are thus of dimension .