Exercise 2.71

Answers

(a)

To have

j

toy types after sampling

i

toys, we either have

j - 1

toy types after sampling

i - 1

toys, and the

i

-th toy is of a previously unseen type, or, we have

j

toy types after sampling

i - 1

toys, and the

i

-th toy has an already seen type.

Thus,

p_{i, j} = p_{i - 1, j - 1} \frac{n - j + 1}{n} + p_{i - 1, j} \frac{j}{n}

(b)

Note that

p_{1, 0} = 0, p_{1, 1} = 1

and

p_{i, j} = 0

for

j > i

. Using strong induction, a proof of the recursion in part

a

follows.

fifthist

2021-12-05 00:00