Exercise 3.14

Answers

(a)

1 - P (X = 0) = 1 - e^{- λ}

P (X \geq 2) = 1 - P (X = 0) - P (X = 1) = (1 - e^{- λ}) - e^{- λ} λ

(b)

P (X = k | X > 0) = \frac{P (X = k)}{P (X > 0)} = \frac{λ^{k}}{(e^{λ} - 1) k!}

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2021-12-05 00:00