Exercise 3.44

Answers

(a)
P(X Y ) Bern(p 2)
(b)
If p1 2, X Y and Y are not independent. Imagine that X = 0 is extremely unlikely. Then, knowing that Y = 0 makes it very likely that X Y = 1. If p = 1 2, then X Y and Y are independent.

X Y and X are independent, since knowledge of X still keeps the probability of Y = 1 at 1 2

(c)

Let the largest element in J be m.

P(Y J = 1) = P(Xm = 1)P(Y J{m} = 0) + P(Xm = 0)P(Y J{m} = 1) = 1 2(P(Y J{m} = 0) + P(Y J{m} = 1)) = 1 2

Thus, Y J Bern(1 2)

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2021-12-05 00:00
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