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Exercise 1.3.4
Let and be sets. Show that there exists a unique set such that if and only if either and or and .
Answers
Proof. Since and are sets, the set uniquely exists by the Axiom of Union. Now let be the property defined by and or and . Consider any such that holds. If and , then obviously . On the other hand, if and , then obviously . Thus, in either case, or so that . Therefore, implies that . Therefore, clearly the set we seek is , which uniquely exists by the Axiom Schema of Comprehension. □
It is worth noting that the set here is called the symmetric difference of and and is introduced in the next section.