Exercise 5.1.13

If A and B are Dedekind infinite, then A × B is Dedekind infinite. [Hint: Use Exercise 1.11.]

Answers

Proof. Suppose that A and B are both Dedekind infinite. Then A contains a countable subset C by Exercise 5.1.11. Also since B is Dedekind infinite it is not finite by Exercise 5.1.8. Hence B so that there is a b B . Clearly then the set

D = { ( a , b ) a C }

is a countable subset of A × B so that A × B is Dedekind infinite by Exercise 5.1.10. □

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2024-07-15 11:42
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