Exercise 5.2.2

A real number x is algebraic if it is a solution of some equation

a n x n + a n 1 x n 1 + + a 1 x + a 0 = 0 ,

where a 0 , , a n are integers. If x is not algebraic, it is called transcendental. Show that the set of algebraic numbers is countable and hence the set of all transcendental numbers has cardinality 2 0 .

Answers

I did not prove this here as I have already done so when studying Rudin’s Principles of Mathematical Analysis, Exercise 2.2.

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2024-07-15 11:42
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