Exercise 6.1.2

ω + 1 is not isomorphic to ω (in the well-ordering by ).

Answers

Proof. Since ω = 𝑵 and ω + 1 = ω { ω } clearly ω is a proper subset of ω + 1 (since ω ω but ω ω + 1 ). Now consider any a ω = 𝑵 and any x < a . Then clearly also x 𝑵 so x ω . Thus ω is an initial segment of ω + 1 . Then, since it has already been shown that both ω and ω + 1 are well-ordered sets, it follows from Corollary 6.1.5a that they cannot be isomorphic. □

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2024-07-15 11:42
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