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Exercise 6.2.6
An ordinal is a natural number if and only if every nonempty subset of has a greatest element.
Answers
Proof. ( ) Suppose that is a natural number and consider any nonempty subset of . Since it follows that so that is finite. Thus is a finite set of natural numbers and so has a greatest element. This can be proven by a trivial inductive argument.
( ) We show this by contrapositive. Suppose that is an ordinal such that . Then so that , from which it follows that Hence or , in which case so that since is transitive. Thus in either case . Clearly has no greatest element (since if were such a greatest element then but ). Thus there is a nonempty subset of such that has no greatest element. □