Exercise 9.1.9

Find some cardinals κ n , λ n ( n 𝑵 ) such that κ n < λ n for all n , but κ n = λ n .

Answers

Let κ n = 2 and λ n = 0 for all n 𝑵 . We claims that these satisfy the requirements.

Proof. Clearly κ n = 2 < 0 = λ n for every n 𝑵 . However, by Exercise 9.1.10 and Theorem 5.2.2c, we then have

κ n = 2 = n < 0 2 = 2 0 = 0 0 = n < 0 0 = 0 = λ n

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2024-07-15 11:42
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