Exercise 10.1

If K is an infinite field and f ( x 1 , x 2 , , x n ) is a non-zero polynomial with coefficients in K , show that f is not identically zero on A n ( K ) . (Hint: Imitate the proof of Lemma 1 in Section 2.)

Answers

Proof. Assume that f vanishes on all of A n ( K ) . We have to prove that f is the zero polynomial.

The proof is by induction on n . If n = 1 , then f is a polynomial with one variable, which vanishes on A 1 ( K ) = K . Since K is infinite, f have more than d roots, where d = deg ( f ) , thus f is the zero polynomial.

Suppose that we have proved the result for n 1 and write

f ( x 1 , , x n ) = i = 0 s 1 g i ( x 1 , , x n 1 ) x n i ,

where the x i are variables, and g i are polynomials in x 1 , , x n 1 .

For all ( a 1 , , a n ) K n ,

0 = f ( a 1 , , a n ) = i = 0 s 1 g i ( a 1 , , a n 1 ) a n i .

From the result for n = 1 , we obtain that the polynomial i = 0 s 1 g i ( a 1 , , a n 1 ) x n i is null, thus for all ( a 1 , , a n 1 ) K n 1 ,

g i ( x 1 , , x n 1 ) = 0 .

The induction hypothesis shows that g i ( x 1 , , x n 1 ) = 0 , thus f ( x 1 , , x n ) = 0 . □

User profile picture
2022-07-19 00:00
Comments