Exercise 6.10

What is ∑ ⁡ a = 1 p − 1 g a ?

Answers

Proof. From Prop. 6.3.1 and Lemma 2,

∑ a = 1 p − 1 g a = g 1 ∑ a = 1 p − 1 ( a p ) = 0 .

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2022-07-19 00:00
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