Exercise 8.2

(false sentence) With the notation of Exercise 1 show that N ( x m = a ) = N ( x d = a ) and conclude that if d i = ( m i , p 1 ) , then i a i x m i = b and i a i x d i = b have the same number of solutions.

Answers

This result is false. I give a counterexample with p = 5 : x + x 3 = 0 𝔽 5 [ x ] has 3 solutions 0 , 2 , 2 . As 3 ( p 1 ) = 3 4 = 1 , the reduced equation is x + x = 0 , which has an unique solution 0 . The true sentence is :

Ex. 8.2 With the notation of Exercise 1 show that N ( x m = a ) = N ( x d = a ) and conclude that if d i = ( m i , p 1 ) , then i a i x i m i = b and i a i x i d i = b have the same number of solutions.

Proof. From Ex. 8.1, we know that

N ( x m = a ) = χ d = 𝜀 χ ( a ) = N ( x d = a ) .

Using this result, we obtain

N ( i = 1 l a i x i m i = b ) = a 1 u 1 + + a l u l = b i = 1 l N ( x m i = u i ) = a 1 u 1 + + a l u l = b i = 1 l N ( x d i = u i ) = N ( i = 1 l a i x i d i = b ) .
User profile picture
2022-07-19 00:00
Comments