Exercise 9.32

Let p be a prime, p 1 ( mod 4 ) and write p = π π ¯ , π [ i ] . Show χ p ( 1 + i ) = i ( p 1 ) 4 .

Answers

Proof.

χ p ( 1 + i ) = χ π ( 1 + i ) χ π ¯ ( 1 + i ) = χ π ( 1 + i ) χ π ( 1 i ) ¯ ( Prop . 9.8 . 3 ( c ) ) = χ π ( 1 + i ) χ π ( 1 i ) = χ π ( i ) ( since ( 1 i ) i = 1 + i ) = i p 1 4 . The last equality is a consequence of the definition of χ π : χ π ( i ) i p 1 4 ( mod π ) , and the classes of 1 , i , i 2 , i 3 modulo π are distinct. □
User profile picture
2022-07-19 00:00
Comments