Exercise 9.42

The notation being as in Section 12 show that the minimal polynomial of g ( χ π ) is x 3 3 px Ap .

Answers

Note : we must read “the minimal polynomial of G = g ( χ π ) + g ( χ π ) ¯ is x 3 3 px Ap ”.

Proof. Write f ( x ) = i = 0 3 a i x i = x 3 3 px Ap .

Then a 3 = 1 , p a 0 = Ap , p a 1 = 3 p , p a 2 = 0 .

Moreover, since 4 p = A 2 + 27 B 2 , p A , therefore p 2 a 0 .

The Eisenstein’s Irreducibility Criterion (Ex. 6.23) shows that f ( x ) is irreducible over . By section 12, G is a root of f , so f is the minimal polynomial of G . □

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2022-07-19 00:00
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