Exercise 11.4 - EM for mixture of Student distributions

Answers

The log-likelihood for the complete data set for the mixture of Student distribution is:

l c ( 𝐱 , z k = 1 ) = π k Γ ( D 2 + v k 2 ) Γ ( v k 2 ) | Σ k | 1 2 v k D 2 π D 2 × ( 1 + 1 v k ( 𝐱 μ ) Σ k 1 ( 𝐱 μ ) ) v k + D 2 .

Following the similar path as exercise 11.2 and exercise 11.3, we have:

Q ( 𝜃 , 𝜃 old ) = n = 1 N k = 1 K r 𝑛𝑘 ( log π k + log ( Γ ( D 2 + v k 2 ) Γ ( v k 2 ) | Σ k | 1 2 v k D 2 π D 2 × ( 1 + 1 v k ( 𝐱 μ ) Σ k 1 ( 𝐱 μ ) ) v k + D 2 ) ) .

The rest is ordinary EM, whose detail symbolic forms is too complex to write down explicitly.

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2021-03-24 13:42
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