Exercise 3.15 - Setting the hyper-parameters I

Answers

Solve for:

\frac{α_{1}}{α_{1} + α_{2}} = m,

\frac{α_{1} \cdot α_{2}}{{(α_{1} + α_{2})}^{2} \cdot (α_{1} + α_{2} + 1)} = v .

We have:

α_{2} = \frac{m \cdot {(1 - m)}^{2}}{v} + m - 1,

α_{1} = α_{2} \cdot \frac{m}{1 - m} .

solour_lfq

2021-03-24 13:42