Задание 127

а) Для функции f(x) = x2 найдите f(1 4); f(−a); f(a + 5).
б) Для функции f(x) = −x3 найдите f(−2);f(−a);0.2 ⋅ f(a2).
в) Для функции f(x) = 1 x3 найдите f(0);f(0.1a); 1 f(a3).
г) Для функции f(x) = xнайдите f(−4);f(0);f(100);f((a − 1)2).

Answers

1.
f(1 4) = (1 4)2 = 1 16;
f(−a) = (−a)2 = a2;
f(a + 5) = (a + 5)2 = a2 + 10a + 25.
2.
f(−2) = −(−2)3 = −(−8) = 8;
f(−a) = −(−a)3 = a3;
0.2 ⋅ f(a2) = 0.2 ⋅−(a2)3 = 0.2 ⋅ (−a6) = −0.2a6
3.
f(0) = 1 0 = ∅
f(0.1a) = 1 (0.1a)3 = 1 0.001a3
1 f(a3) = 1 1 a9 = a9
4.
f(−4) = −4 = ∅
f(0) = 0 = 0;
f(100) = 100 = 10;
f((a − 1)2) = (a − 1)2 = |a − 1|
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2021-07-27 00:00
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