Exercise I.C.4

Let V be a vector space, and let ϕ Hom(V V ). Show that

ϕ is injective ϕ is surjective ϕ is an isomorphism

Answers

We use the ring strategy to demonstrate the equivalence.

  • Suppose that ϕ is injective. dim (ker ϕ) = 0. Then dim (V ) = dim (ϕ(V )), and so from ϕ(V ) V follows V = ϕ(V ) and ϕ is surjective.
  • Follows by Corollary 1.
  • Follows by definition.
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2021-10-30 12:14
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