Proposition I.6

Please fill in the exercise text.

Answers

Let (V V,+,) over 𝕂 be an algebra of endomorphisms of V .

  • Suppose that ϕ V V such that there exists φ V V with ϕφ = and φϕ =. We show that

    y V !x V : ϕ(x) = y

    Existence: let y V be arbitrary. Denote x := φ(y). We then have

    ϕ(x) = ϕ(φ(y)) = (y) = y

    as desired. Now we show uniqueness. Suppose that we have x,x V with ϕ(x) = y and ϕ(x) = y. Then φ(y) = φ(ϕ(x)) = x and φ(y) = φ(ϕ(x)) = x, and so x = x.

  • If ϕ is an isomorphism, then by definition ϕ1 is its inverse with respect to .
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2021-10-30 12:19
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