Задание 5, стр 8

Question

Заполните таблицу.
$$a = 4, b = 32\Rightarrow \sqrt{a+b} = ??$$
$$a = 33, b = -8\Rightarrow \sqrt{a+b} = ??$$
$$a = -25, b = 26\Rightarrow \sqrt{a+b} = ??$$
$$a = 1, b = 0,21\Rightarrow \sqrt{a+b} = ??$$
$$a = 2, b = 0,25\Rightarrow \sqrt{a+b} = ??$$
$$a = -2, b = 11\Rightarrow \sqrt{a+b} = ??$$
$$a = 0,4, b = 0,09\Rightarrow \sqrt{a+b} = ??$$
$$a = 0,4, b = -0,04\Rightarrow \sqrt{a+b} = ??$$
$$a = 9, b = 16\Rightarrow \sqrt{a+b} = ??$$
$$a = 64, b = 36\Rightarrow \sqrt{a+b} = ??$$

Gimli · Accepted Answer

\begin{enumerate}
\item $$a = 4, b = 32\Rightarrow \sqrt{a+b} = \sqrt{4+32} = \sqrt{36} = \sqrt{6^2} = 6;$$
\item $$a = 33, b = -8\Rightarrow \sqrt{a+b} = \sqrt{33-8} = \sqrt{25} = \sqrt{5^2} = 5;$$
\item $$a = -25, b = 26\Rightarrow \sqrt{a+b} = \sqrt{-25+26} = \sqrt{1} = \sqrt{1^2} = 1;$$
\item $$a = 1, b = 0,21\Rightarrow \sqrt{a+b} = \sqrt{1 + 0,21} = \sqrt{1,21} = \sqrt{1,1^2} = 1,1;$$
\item $$a = 2, b = 0,25\Rightarrow \sqrt{a+b} = \sqrt{2 + 0,25} = \sqrt{2,25} = \sqrt{1.5^2} = 1.5;$$
\item $$a = -2, b = 11\Rightarrow \sqrt{a+b} = \sqrt{-2+11} = \sqrt{9} = \sqrt{3^2} =3;$$
\item $$a = 0.4, b=0.09\Rightarrow \sqrt{a+b} = \sqrt{0.4+0.09} = \sqrt{0.49} = \sqrt{0.7^2} =0.7;$$
\item $$a = 0,4, b = -0,04\Rightarrow \sqrt{a+b} = \sqrt{0.4+(-0.04)} = \sqrt{0.4-0.04} = \sqrt{0.36}= \sqrt{0.6^2} = 0.6;$$
\item $$a = 9, b = 16\Rightarrow \sqrt{a+b} = \sqrt{9+16} = \sqrt{25} = \sqrt{5^2} = 5;$$
\item $$a = 64, b = 36\Rightarrow \sqrt{a+b} = \sqrt{64+36} = \sqrt{100} = \sqrt{10^2} = 10.$$
\end{enumerate}

Задание 5, стр 8

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Задание 5, стр 8

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