Задание 8, стр 22

Question

Найдите значение выражения.
$$\mathrm{a}) \sqrt{8} \cdot \sqrt{50}\quad
\mathrm{b}) \sqrt{13} \cdot \sqrt{52}\quad
\mathrm{c}) \sqrt{63} \cdot \sqrt{7}\quad
\mathrm{d}) \sqrt{14} \cdot \sqrt{21} \cdot \sqrt{6}$$
$$\mathrm{e}) \frac{\sqrt{2}}{\sqrt{8}}\quad \mathrm{f}) \frac{\sqrt{13}}{\sqrt{52}}\quad g) \frac{\sqrt{7,5}}{\sqrt{0,3}}\quad h) \frac{\sqrt{10} \cdot \sqrt{15}}{\sqrt{6}}$$

Gimli · Accepted Answer

\begin{enumerate}[label=(alph*)]
\item $$\sqrt{8 \cdot 50}=\sqrt{400}=\sqrt{20^{2}}=20$$
\item $$\sqrt{13 \cdot 52}=\sqrt{13 \cdot 13 \cdot 4}=\sqrt{13^{2} \cdot 4}=\sqrt{13^{2}}\cdot \sqrt{4}=13 \cdot 2=26$$
\item $$\sqrt{63} \cdot \sqrt{7}=\sqrt{63 \cdot 7}=\sqrt{9 \cdot 7 \cdot 7}=\sqrt{9 \cdot 7^{2}}=\sqrt{9} \cdot \sqrt{7^{2}}=3 \cdot 7=21$$
\item $$\sqrt{14} \cdot \sqrt{21} \cdot \sqrt{6}=\sqrt{14 \cdot 21 \cdot 6}=\sqrt{7 \cdot 2 \cdot 7 \cdot 3 \cdot 6}=\sqrt{7 \cdot 7 \cdot 2 \cdot 3 \cdot 6}=\sqrt{7^{2} \cdot 6 \cdot 6}=\sqrt{7^{2} 6^{2}}=\sqrt{7^{2}} \cdot \sqrt{6^{2}}=7 \cdot 6=$$ $$=42$$
\item $$\frac{\sqrt{2}}{\sqrt{8}}=\sqrt{\frac{2}{8}}=\sqrt{\frac{1}{4}}=\sqrt{\left(\frac{1}{2}\right)^{2}}=\frac{1}{2}$$
\item $$\sqrt{\frac{13}{52}}=\sqrt{\frac{13}{52}}=\sqrt{\frac{1}{4}}=\sqrt{\left(\frac{1}{2}\right)^{2}}=\frac{1}{2}$$
\end{enumerate}

Задание 8, стр 22

Answers

Comments

Задание 8, стр 22

Answers

Comments

Add answer