Задание 13, стр 26

Question

Выполните действия.
ewline
a) $\sqrt{3} \cdot(\sqrt{12}+\sqrt{2})$
ewline
b) $\sqrt{2} \cdot(\sqrt{5}-3 \sqrt{2})$
ewline
c) $(4 \sqrt{3}-\sqrt{6}) \cdot 2 \sqrt{3}$
ewline
d) $(\sqrt{12}+2 \sqrt{18}) \cdot \sqrt{2}-2 \sqrt{6}$

Gimli · Accepted Answer

$a)\quad \sqrt{3}(\sqrt{12}+\sqrt{2})=\sqrt{3} \cdot \sqrt{12}+\sqrt{3} \cdot \sqrt{2}=\sqrt{36}+\sqrt{6}=6+\sqrt{6}$
ewline
$b)\quad \sqrt{2}(\sqrt{5}-3 \sqrt{2})=\sqrt{2} \cdot \sqrt{5}-\sqrt{2} \cdot 3 \sqrt{2}=\sqrt{10}-3 \cdot 2=\sqrt{10}-6.$
ewline
$c)\quad (4 \sqrt{3}-\sqrt{6}) \cdot 2 \sqrt{3}=4 \sqrt{3} \cdot 2 \sqrt{3}-\sqrt{6} \cdot 2 \sqrt{3}=8 \cdot 3-2 \sqrt{18}=24-2 \cdot \sqrt{9} \cdot \sqrt{2}=24-2 \cdot 3 \cdot \sqrt{2}=24-6 \sqrt{2}.$
ewline
$d)\quad (\sqrt{12}+2 \sqrt{18}) \cdot \sqrt{2}-2 \sqrt{6}=\sqrt{12} \cdot \sqrt{2}+2 \sqrt{18} \cdot \sqrt{2}-2 \sqrt{6} = \sqrt{24} + 2\sqrt{36} - 2\sqrt{6} = \sqrt{4}\cdot \sqrt{6} +2\cdot 6 - 2\sqrt{36} =$
$\qquad = 2\sqrt{6}+12-2\sqrt{6} = 12. $

Задание 13, стр 26

Answers

Comments

Задание 13, стр 26

Answers

Comments

Add answer