Homepage › Solution manuals › Найма Гахраманова › Математика - 8 › Задание 1, стр 109
a) (b c −c b ) ⋅ bc b−cb) 3a−18 a2−25 ⋅ (1 − 1 6−a )c) ( a a+1 + 1) : 2a a+1d) (a+b a−b −a−b a+b ) : 2ab a2−b2e) 1−2x 2x+1 + x2+3x 4x2−1 : 3+x 4x−2f) 2x−y xy − 1 x+y ⋅ (x y −y x ) .
a) (b c −c b ) ⋅ bc b−c = b2−c2 bc ⋅ bc b−c = b2−c2 b−c = (b−c)(b+c) b−c = b + cb) 3a−18 a2−25 ⋅ (1 − 1 6−a ) = 3(a−6) (a−5)(a+5) ⋅6−a−1 6−a = 3(a−6) (a−5)(a+5) ⋅5−a 6−a = (−3)⋅(−1) a+5 = 3 a+5.c) ( a a+1 + 1) : 2a a+1 = a+a+1 a+1 ⋅a+1 2a = 2a+1 a+1 ⋅a+1 2a = 2a+5 2a d) (a+b a−b −a−b a+b ) ⋅a2−b2 2ab = (a+b)2−(a−b)2 (a−b)(a+b) ⋅a2−b2 2ab = = a2+2ab+b2−a2+2ab−b2 a2−b2 , a2−b2 2ab = 4ab 2ab = 2.e) 1−2x 2x+1 + x2+3x 4x2−1 : 3+x 4x−2 = 1−2x 2x+1 + x2+3x (2x−1)(2x+1) ⋅4x−2 3+x = 1−2x 2x+1 + x(x+3) (2x−1)(2x+1) ⋅2(2x−1) 3+x = = 1−2x 2x+1 + x⋅2 2x+1 = 1−2x+2x 2x+1 = 1 2x+1f)2x−y xy − 1 x+y ⋅ (x y −y x ) = 2x−y xy − 1 x+y ⋅x2−y2 xy = 2x−y xy − 1 x+y ⋅(x−y)(x+y) xy = 2x−y xy −x−y xy = 2x−y−x+y xy = x xy = 1 y
