Задание 12 стр 115

Answers

 a) x + 1 x + 2 x2 4 x2 + 2x : x2 4x + 4 x2 + x = x + 1 x + 2 (x 2)(x + 2) x(x + 2) x2 + x x2 4x + 4 = = x + 1 x + 2 x 2 x x(x + 1) (x 2)2 = x + 1 x + 2 x + 1 x 2 = = (x + 1)(x 2) (x + 2)(x 2) (x + 1)(x + 2) (x + 2)(x 2) = x2 + x 2x 2 (x + 2)(x 2) x+2 (x+2)2x+2(x 2) = x2 x 2 (x + 2) x2 + 3x + 2 (x + 2)(x 2) = x2 x 2 x2 3x 2 (x + 2)(x 2) = 4x 4 (x + 2)(x 2) = 4x + 4 (x + 2)(x 2) = 4x + 4 x2 4 = 4(x + 1) 4 x2 .  b) 2 x x 4 + x2 2x 3 x2 x 6 x2 + 2x x2 4x x2 2x 3 = 0 D = 4 + 12 = 16 = 42 x1 = 6 + D 2a = 2 + 4 2 = 3;x2 = 2 4 2 = 2 2 = 1. x2 2x 3 = (x 3)(x + 1) x2 x 6 = 0 D = 1 + 24 = 25 = 52 x1 = 6 + D 2a = 1 + 5 2 = 3;x2 = b D 2a = 1 5 2 = 4 2 = 2. x2 x 6 = (x 3)(x + 2) 2 x x 4 + (x 3)(x + 1) (x 3)(x + 2) x(x + 2) x(x 4) = = 2 x x 4 + x + 1 x + 2 x(x + 2) x(x 4) = 2 x x 4 + x + 1 x 4 = = 2 x + x + 1 x 4 = 3 x 4.

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2023-01-17 14:02
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