Задание 5, стр 48

Question

Решите уравнение.
\begin{enumerate} 
\item $2 x^2=0$
\item $x^2-16=0$
\item $-2 x^2=-50$
\item $8 x^2=2 x^2$
\item $x^2-3=0 ; \quad$ 
\item $2 x^2+x=0$;
\item $2 x^2+8=0$
\item $3 x=2 x^2$
\end{enumerate}

Gimli · Accepted Answer

$$\begin{array}{rcc}	ext{1) }2 x^2=0 & 	ext { 2) } x^2-16=0 & 	ext { 3) }-2 x^2=-50 \ x^2=0: 2 & x^2=16 & \frac{-2 x^2}{-2}=\frac{-50}{-2} \ x^2=0 & x=\pm \sqrt{16} & x^2=25 \ x=0 & x=\pm 4 & x=\pm 5 .\end{array}$$

ewline
$$\begin{array}{rcc}	ext{4) }8 x^2=2x^2 & 	ext { 5) } x^2-3=0 & 	ext { 6) }2 x^2+x=0 \ 8x^2-2x^2=0 & x^2=3 & x(2x+1)=0 \ 6x^2=0 & x=\pm \sqrt{3} & \begin{array}{l}x=0 \ 2 x+1=0\end{array}  \ x^2=0 & & \begin{array}{l}x=0 \x=-0.5\end{array} .\end{array}$$

\begin{description}
\item[7)] $2 x^2+8=0 \quad$
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$2 x^2=-8 \quad$
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$x^2=-\frac{8}{2}$
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$x^2=-4$
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$x \in\{\varnothing\}$
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\item[8)] $3 x=2 x^2$
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$3 x-2 x^2=0$
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$2 x^2-3 x=0$
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 $x(2 x-3)=0$
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 $\left\{\begin{array}{l}x=0 \ 2 x-3=0\end{array} \Leftrightarrow\left\{\begin{array}{l}x=0 \ 2 x-3\end{array} \Leftrightarrow\left\{\begin{array}{l}x=0 \ x=1,5\end{array}ight.ight.ight.$
\end{description}

Задание 5, стр 48

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Задание 5, стр 48

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