Homepage › Solution manuals › Найма Гахраманова › Математика - 8 › Задание 7, стр 101
a)x2−2x y ⋅y2 x b) a−b ab ⋅ 3ab ab−b2c) (3x − 15y) ⋅ 4 x2−25y2d) a (a−2)(a+2) ⋅ (a − 2)2e) c2−16 15bc ⋅ 5b c+4.f) (x+3)2 2(x−2) ⋅(x−2)(x+2) 3(x+3) −(x+3)(x+2) 3⋅2 .
a) x2−2x y ⋅y2 x = x(x−2) y ⋅y2 x = y(x − 2) = xy − 2y.b) a−b ab ⋅ 3ab ab−b2 = a−b ab ⋅ 3ab b(a−b) = 3 b.c) (3x − 15y) ⋅ 4 x2−25y2 = 3(x − 5y) ÷ 4 (x−5y)(x+5y) = 12 x+5yd) a (a−2)(a+2) ⋅ (a − 2)2 = a⋅(a−2) a+2 .e) c2−16 15bc ⋅ 5b c+4 = (c−4)(c+4) 5b⋅3c ⋅ 5b c+4 = c−4 3c .f) (x+3)2 2(x−2) ⋅(x−2)(x+2) 3(x+3) −(x+3)(x+2) 3⋅2 = (x+3)(x+2) 6 .