Exercise 10.A.17

Answers

Proof. Let u1,,um be a basis of null T. Extend it to a basis u1,,um,v1,,vn of V . Then Tv1,,Tvn is a basis of range T (see the proof of 3.22). Define a linear map S : range T V by

S(Tv j) = vj

for j = 1,,n. We can extend S to an operator S on V . Regardless of how we extend S, it is clear that the matrix of ST will be of the following form

M(ST,(u1,,um,v1,,vn)) = (0 0 1 1 ),

where the 1’s appear on the last n diagonal entries. However, the trace of this matrix should equal 0 (since trace (ST) = 0). Hence n = 0, because the 1’s should not appear in any of the columns. Therefore T = 0. □

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2017-10-06 00:00
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