Exercise 2.A.16

Answers

Proof. Let C[0,1] denote the real vector space of all continuous real-valued functions on the interval [0,1]. Since every polynomial is continuous on [0,1], it follows that P() is a subspace of C[0,1]. However, P() is infinite-dimensional (by 2.16). Thus 2.26 now implies that C[0,1] is infinite-dimensional. □

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2017-10-06 00:00
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