Exercise 2.C.8

(a) Let U = { p P 4 ( R ) : 1 1 p = 0 } . Find a basis of U.

(b) Extend the basis in part (a) to a basis of P 4 ( R ) .

(c) Find a subspace W of P 4 ( R ) such that P 4 ( R ) = U W .

Answers

(a) given the condition that 1 1 p = 0 , we can conclude that p must be an odd function. For a polynomial to be odd, it must only have odd powers of x in it. Therefore, p = a 1 x 3 + a 2 x . Thus, x , and x 3 are a basis of U .

(b) To extend it, we only have to add on 1 , x 2 , and x 4 to make it be a basis of P 4 ( R ) .

(c)

W = { p P 4 ( R ) : 1 0 p = 0 1 p }

User profile picture
2025-03-18 18:33
Comments