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Exercise 4.2
Suppose is a positive integer. Is the set
a subspace of ?
Answers
Proof: Let the space in the problem be known as . Then, we want to prove closure upon addition and multiplication. Then, , we want to show and . First, define and where
and,
Then to prove additive closure,
which clearly also has degree of either or . For multiplicative closure,
which also clearly has degree or . Hence, due to its closure additively and multiplicatively, is a subspace.