Exercise 3.C.12

Answers

Proof. We have

(\begin{matrix} 1 & - 1 \\ 1 & - 1 \end{matrix}) (\begin{matrix} 1 & 1 \\ - 1 & - 1 \end{matrix}) = (\begin{matrix} 2 & 2 \\ 2 & 2 \end{matrix}),

but

(\begin{matrix} 1 & 1 \\ - 1 & - 1 \end{matrix}) (\begin{matrix} 1 & - 1 \\ 1 & - 1 \end{matrix}) = (\begin{matrix} 2 & - 2 \\ - 2 & 2 \end{matrix}) .

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celiopassos

2017-10-06 00:00