Exercise 3.D.8

Answers

Proof. Let w1,,wn be a basis of W and v1,,vn an inverse image of this basis when T is applied. Because w1,,wn is linearly independent, it follows that v1,,vn is also linearly independent (you can check it).

Define U by

U = span(v1,,vn)

It easy to see that T|U is both injective and surjective. Hence T|U is an isomorphism of U onto W. □

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2017-10-06 00:00
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