Exercise 3.E.8

Answers

Direction 1, A is an affine subset:
Obviously we can define A as,

A = v + U

where v V and U is a subspace of V .
Let

x = v + u 1

and,

w = v + u 2

where u 1 , u 2 U . Additionally define

u 3 = λ ( u 1 u 2 ) + u 2

Clearly, u 3 U So

v + u 3 A λ ( v v ) + v + λ ( u 2 u 2 ) + u 2 A λ ( v + u 1 ) + ( v + u 2 ) λ ( v + u 2 ) A λ x + ( 1 λ ) w A
(2)

Direction 2, λ v + ( 1 λ ) w A
Now we are going to prove that A is a subspace of V and is thus an affine subset of V .
Homogeneity: Let v = w . Thus,

λ v + ( λ 1 ) v A ( 2 λ 1 ) v A
(3)

Additivity: Let λ = 1 2 .

1 2 v + 1 2 w A v + w A
(4)

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2025-06-02 23:49
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