Exercise 3.F.36

Answers

Proof. (a) We have

\begin{aligned} null i^{'} & = {φ \in V^{'} : i^{'} (φ) = 0} \\ = {φ \in V^{'} : i^{'} (φ) (u) = 0 for every u \in U} \\ = {φ \in V^{'} : φ \circ i (u) = 0 for every u \in U} \\ = {φ \in V^{'} : φ (u) = 0 for every u \in U} \\ = {φ \in V^{'} : φ \in U^{0}} \\ = U^{0} \end{aligned}

□

celiopassos

2017-10-06 00:00