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Exercise 3.F.3

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Proof. Since $v$ is non-zero, we can extend it to a basis $v, v_{1}, \dots, v_{n}$ of $V$ . Let $φ, φ_{1}, \dots, φ_{n}$ be the dual basis of $v, v_{1}, \dots, v_{n}$ . By definition of dual basis, we have $φ (v) = 1$ , as desired. □

celiopassos

2017-10-06 00:00

Exercise 3.F.3

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