Exercise 5.A.22

Answers

Proof. If $w = - v$ , then clearly $- 3$ is an eigenvalue of $T$ . If $w \neq - v$ , then $v + w \neq 0$ and

T (v + w) = Tv + Tw = 3 w + 3 v = 3 (v + w) .

Hence $3$ is an eigenvalue of $T$ . □

celiopassos

2017-10-06 00:00